题目1 : Give My Text Back

时间限制:10000ms

单点时限:1000ms

内存限制:256MB

描述

To prepare for the English exam Little Ho collected many digital reading materials. Unfortunately the materials are messed up by a malware.

It is known that the original text contains only English letters (a-zA-Z), spaces, commas, periods and newlines, conforming to the following format:

1. Each sentence contains at least one word, begins with a letter and ends with a period.

2. In a sentence the only capitalized letter is the first letter.

3. In a sentence the words are separated by a single space or a comma and a space.

4. The sentences are separated by a single space or a single newline.

It is also known the malware changes the text in the following ways:

1. Changing the cases of letters.

2. Adding spaces between words and punctuations.

Given the messed text, can you help Little Ho restore the original text?

输入

A string containing no more than 8192 English letters (a-zA-Z), spaces, commas, periods and newlines which is the messed text.

输出

The original text.

样例输入

my Name  is Little   Hi.His   name IS Little ho  ,  We are   friends.

样例输出

My name is little hi.His name is little ho, we are friends.

题目大意

小Hi和小Ho为了准备英语的期末考试，找了很多英语的电子资料。但是由于U盘出了问题，导致资料内容变得很乱。于是小Hi和小Ho决定写一个程序去将所有的电子资料格式化。 已知每一份资料只包含大小写字母，‘ ’(空格), ‘,’(逗号)，‘.’(句号)以及换行符。小Hi和小Ho希望整理后的资料为如下格式： - 每一句话都是以’.’结尾，每一段话都是以换行符结尾。 - 每一段开始没有空格。 - 每一个句子都是完整的，即至少包含1个单词，句末一定为‘.’(句号)。 - 每一句话只有首字母大写。 - 每句话内单词之间由1个空格隔开。 - 标点符号与前面的单词之间无空格，标点符号后有1个空格或换行符。 对于给定的资料，请你对其进行格式化，并输出格式化的结果。

 

解题思路：

讲每行输入的数据先全部小写化处理，然后检测，空格，连续的空格就行删除，只留一个，逗号和句号后面加空格，因为需要对数组进行直接插入删除操作，所以用vector<char>，，，为什么不用list，因为list链表分配的不是连续的地址，不能通过下标直接存取。代码本地通过了，不过，提交没有AC，只能等下周答案出来了，看看别人的程序，再做修改。

 

1 #include "iostream" 2 #include "string" 3 #include "vector" 4  5 using namespace std; 6  7 int main() 8 { 9     char s[10000];10     bool point_tag = false;11 12     while (cin.getline(s, 10000))13     {14         int i = -1,len;15         vector
          
            input;                16 17         while (s[i++])18         {19             s[i] = tolower(s[i]);20         }21         len = i;22         i = 0;23         s[i] = toupper(s[i]);24 25         for (int i = 0; i < len; i++)26         {27             input.insert(input.begin() + i, s[i]);28         }29 30         for (int i = 0; i < input.size(); i++)31         {32             if (input[i] == ' ')33                 while (input[i + 1] == ' ' || input[i + 1] == ',')34                 {35                     if (input[i] == ',') {36                         input.insert(input.begin() + i + 1, ' ');37                         break;38                     }39                         40                     else41                         input.erase(input.begin() + i);42                 }    43             else if (input[i] == '.')44             {45                 input.insert(input.begin() + i + 1, ' ');46                 char c = input[i + 2];47                 c = toupper(c);48 49                 input.erase(input.begin() + i + 2);50                 input.insert(input.begin() + i + 2, c);51             }            52         }53 54         for (int i = 0; i < input.size(); i++)55         {56             if (input[i] == '.')57             {58                 char c = input[i + 2];59                 c = toupper(c);60 61                 input.erase(input.begin() + i + 2);62                 input.insert(input.begin() + i + 2, c);63             }64             cout << input[i];65         }    66         cout << endl;67     }68 }
          

不能AC的痛！